Rules for puzzles

@nadjarostowa said in #10:
> Your first example is a contrived example of an unsolvable puzzle.
Unsolvable yet prone to succeed at it by guess, and so having some finite rating (very low in this extreme case).

>The rating of the puzzles directly reflects people succeeding and failing at it. If there would be several "correct" moves, this would not change anything in that regard.
Sure but the rating of the puzzles would be closer to their real difficulty, which is the objective of my suggestion.

nadjarostowa

#12

@SIM62 said in #11:
> Unsolvable yet prone to succeed at it by guess, and so having some finite rating (very low in this case).

The rating of the puzzle would depend on who plays it. If only 1000 rated players play it (and solve 50%), it will be rated 1000. If only 2800 GMS play it (again at 50%), it will be rated 2800. For a mixture, it will be in between.

One could think it gets a pretty average rating. :-)

> Sure but the rating of the puzzles would be closer to their real difficulty, which is the objective of my suggestion.

I am not convinced. The current rating *does* reflect the difficulty pretty good. Yes, sometimes you can simply guess the move. Knowing it is a puzzle and has a unique solution makes things easier. But if everyone guesses it right, the low rating of the puzzle will reflect that. And I don't see how more (alternate) solutions would change that.

SIM62 edited

#13

@nadjarostowa said in #12:
> The rating of the puzzle would depend on who plays it.
In theory, it would not.
> If only 1000 rated players play it (and solve 50%), it will be rated 1000. If only 2800 GMS play it (again at 50%), it will be rated 2800.
It is impossible for a good puzzle that the success rate at it will be the same for 1000 rated players and for 2800 rated players. That will be the case for the extremely silly puzzle in my first post.
> But if everyone guesses it right, the low rating of the puzzle will reflect that. And I don't see how more (alternate) solutions would change that.
May be my explanation was poor... If the guesser is required to continue he will more likely fail eventually. The number of the right guesses will be smaller.